Varargs

Variable-argument methods

Varargs let a method accept any number of same-type arguments — zero, one, or many — without the caller building an array explicitly:

public static int sum(int... nums) {
    int total = 0;
    for (int n : nums) total += n;
    return total;
}

sum(1, 2, 3);             // caller passes comma-separated values
sum(new int[]{1, 2, 3}); // or an explicit array — both work
sum();                    // zero args is valid

Inside the method, nums is a plain int[]. The three-dot syntax is purely compiler sugar: it builds the array on the caller's behalf.

Rules: - A varargs parameter must be last in the parameter list. - A method may have at most one varargs parameter. - Overload ambiguity: if multiple overloads each match a call, the compiler reports an error rather than guessing. Varargs overloads are considered last in resolution (after exact match and widening), so a specific overload wins when available.